Respostas

  • Usuário do Brainly
2014-08-15T15:27:09-03:00
Temos que, (x-y)^3=x^3-3x^2y+3xy^2-y^3.

Assim,

(a^2b-ab^2)^3=(a^2b)^3-3\cdot(a^2b)^2\cdot(ab^2)+3\cdot(a^2b)\cdot(ab^2)^2-(ab^2)^3.

Logo, (a^2b-ab^2)^3=a^6b^3-3a^5b^4+3a^4b^5-a^3b^6.
1 4 1