Respostas

2013-08-12T17:00:11-03:00
Se for fzr por bhaskara eu axo q fica assim x²-x=0 1+- raiz de (-1)²-4.1.0/2.1
1+- raiz de 1/2=1+-1/2  X=1+1/2=1   e X=1-1/2=0
2013-08-12T17:05:09-03:00
X²=x
x²-x=0

Δ=(-1)²-4*1*0
Δ=1

x'= -1+1/2= 0

x''= -1-1/2= -1