Respostas

2014-08-20T14:43:30-03:00
Olá!

x^2 - 7x + 12 = 0

\Delta = b^2 - 4*a*c\\
\Delta = (-7)^2 - 4*1*12\\
\Delta = 49 - 48\\
\Delta = 1
\\\\
x = \frac{- b \±  \sqrt{\Delta}}{2*a} 
x = \frac{- (-7) \±  \sqrt{1}}{2*1} 
\\\\
x = \frac{7 \±1}{2} \\\\
x1 =  \frac{8}{2}\\\\
x1 = 4\\\\\\\ \\
x2 = \frac{6}{2} \\\\ x2 = 3
As raízes da equação são {3,4}.

Espero que tenha ajudado!