Respostas

2014-08-24T03:33:07-03:00
X+y+z=-3 -L1+L2 x+y+z=-3
x+y+3z=9 --> 2z=12
3x+y-2z=-14 -3L1+L3 -2y-5z=-5

L2<->L3 x+y+z=-3
--> -2y-5z=-5
2z=12

z=6. y=25/-2. x=-31/2

s{( -31/2, 25/-2, 6)}




-L1+L3 -3L1+L3
-x-y-z=3 -3x-3y-3z=-9
x+y+3z=9 3x+y-2z=-14
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2z=12 -2y-5z=-23



obs..L2<->L3= inverter a posiçao das equações