Respostas

2014-08-27T22:08:08-03:00
(\frac{3x^{\frac{3}{2}}y^3}{x^2y^{\frac{-1}{2}}} ) ^{-2}=(\frac{ \sqrt{3x^3}y^3 }{x^2 \frac{1}{y^2}})^{-2}\\\frac{1}{ \frac{\sqrt{3x^3}y^3 }{\frac{x^2}{y^2}}}=\frac{1}{ \sqrt{3x^3}y^3 }.\frac{y^2}{x^2}=\frac{y^2}{ \sqrt{3x^3}y^3x^2 }=\frac{1}{ \sqrt{3x^3}yx^2 }=\frac{ \sqrt{3x^3}yx^2 }{(\sqrt{3x^3}yx^2)^2}

\frac{ \sqrt{3x^3}yx^2 }{(\sqrt{3x^3}yx^2)^2}=\frac{\sqrt{3x^3}yx^2}{3x^3y^2x^4}=\frac{ \sqrt{3x^3} }{3x^5y}
Veja se está certo kkkkk , Fiz na correria