Respostas

2014-08-28T18:04:20-03:00
Uma alternativa sem usar o binômio de Newton

(2-2i)^9\\
\\(2(1-i))^9\\
\\2^9(1-i)^9\\
\\2^9(1-i)^3(1-i)^3(1-i)^3\\
\\2^9(-2-2i)(-2-2i)(-2-2i)\\
\\2^9(16-16i)\\
\\2^9(2^4-2^4i)\\
\\2^{13}-2^{13}i\\

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