Respostas

2013-08-22T13:35:38-03:00
\frac{x = -b  +/-  \sqrt{ b^{2} - 4ac}}{2a} =
\frac{x= -(-6) +/-  \sqrt{  (-6^{2}) - 4(1)(8)}}{2(1)}= 
 \frac{x= +6 +/-  \sqrt{36 - 32} }{2}=
 \frac{x= +6 +/-  \sqrt{4} }{2}=
  
x^{1}=  \frac{6+2}{2} =  \frac{8}{2}= 4 ///
x^{2}= \frac{6-2}{2} = \frac{4}{2}= 2 ///
 


OBS:::: X¹ e X² são separados !