Respostas

2013-08-22T00:16:27-03:00
L = 2,6 m 
A = 0 ,7 m
r= 1,7.10^-8

R = r. \frac{L}{A}


R = \frac{1,7.10^{-8}.2,6}{0,7} =  \frac{4,42.10^{-8}}{0,7} = 6,31.10^{-8} ohm